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Archiver > DEED-MAPPER-USERS > 2004-04 > 1082133593

From:
Subject: Re: Re[DMU] Help fpr deed with arc
Date: Fri, 16 Apr 2004 12:39:53 -0400

It's just geometry. The radius of the circle is given and so was the
length of the arc. Find the circumfrence of the entire circle and
then the ratio of the arc to the circumfrence.
c=2 X 3.14 X r or abt 6200 ft in this case
1736 ft/ 6200 ft = .280 or almost one third of the circle.
360 degrees X .280= 101degrees of arc is being swept. In other words
for every 10 degrees 173.6 ft is being covered.
So if you divide the given length into ten equal segments and change
the angle by ten degrees each time you can get an approximation of
the curve. If you wanted to you could do it even finer but 10 seemed
a good number.
As for down the meanders I just find where I am on the map and use
the lat/ long feature [the +] to "walk" my way down the meander and
write down the direction and distance as I go.

Charlotte

> Do you have a convenient algorithm (or better a program) for
> calculating this? If so, how about passing it on to Steve Broyles for
> incorporation into a future release. Or even better, since most of
> these kinds of interpolations are necessarily irregular (eg. "down the
> meanders...") would be the ability to plot a series of points (at the
> bends, say, of a river) and have the bounds generated automagically by
> the program, connecting the plotted dots (this is assuming the
> presence of one of Steve's overlays, or other importations showing
> river course and the like).
>
> ----- Original Message -----
> From: <>
> To: <>
> Sent: Friday, April 16, 2004 9:29 AM
> Subject: Re[DMU] Help fpr deed with arc
>
>
> > ok your arc is sweeping an arc of 101.0349 degrees during it's
> > length.
> > You can enter the following ten lines in place of the instruction
> > Lm ; 1736.89f; this is the arc
> >
> > lm s59.89e; 173.689f;
> > pt
> > lm s69.89e; 173.689f;
> > pt
> > lm s79.89e; 173.689f;
> > pt
> > lm s89.89e; 173.689f;
> > pt
> > lm n79.89e; 173.689f;
> > pt
> > lm n69.89e; 173.689f;
> > pt
> > lm n59.89e; 173.689f;
> > pt
> > lm n49.89e; 173.689f;
> > pt
> > lm n39.89e; 173.689f;
> > pt
> > lm n29.89e; 173.689f;
> > This is dividing the given arc up into 10 equal segments. It is an
> > approximation and not a smooth arc but will do for display
> > purposes.
> >
> >
> > Charlotte
> >
> > > I know DeedMapper can't do arcs but can I somehow get the rest of
> > > the points in the correct position while leaving out the segment
> > > with the arc?
> >
> >
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>
>
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