GENEALOGY-DNA-L Archives

Archiver > GENEALOGY-DNA > 2005-09 > 1127340010


From: (John Chandler)
Subject: Re: Felstead TMRCA, hg E3b (was Re: [DNA] SMGF adjustments to FTDNA values)
Date: Wed, 21 Sep 2005 18:00:10 -0400 (EDT)
References: <380-220059220214337977@M2W087.mail2web.com> <43308839.6020402@dna-fingerprint.com> <REME20050920182157@alum.mit.edu> <op.sxfa9wsxpqnhvj@pablo> <009001c5be39$39effe50$0100a8c0@chrissam> <op.sxfdbclzpqnhvj@pablo> <00c101c5be3e$424f7300$0100a8c0@chrissam> <001c01c5beb5$a6d62fe0$0100a8c0@chrissam> <op.sxg1kudbpqnhvj@pablo>
In-Reply-To: <op.sxg1kudbpqnhvj@pablo> (dave_reynolds@mentor.com)


David wrote:
> Question to TMRCA experts on the list: Given the above, how might
> one calculate a TMRCA for a common ancestor to all four lines, given
> that an ancestral haplotype cannot be deduced from the above data.

About the best you can do here is estimate the TMRCA separately for
each pair and pick the biggest estimate. Anyone who is more recent
than the max TMRCA will fail to be an ancestor of somebody in the
group. With only four lines, you can't get any extra mileage out
of statistical games.

John Chandler

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