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Archiver > GENEALOGY-DNA > 2011-01 > 1294183555


From: "Ken Nordtvedt" <>
Subject: Re: [DNA] How old is Y-Chromosome Adam?
Date: Tue, 4 Jan 2011 16:26:05 -0700
References: <201101040808.p0488xgP020485@mail.rootsweb.com><AA814106-788F-475B-9494-D839E21F7AC6@vizachero.com><AANLkTi=FN3NEtEsp93qpYyLSr_tD9PLJb+pRZm+HHpv7@mail.gmail.com><00e301cbac30$3bb02b80$c2482dae@Ken1><AANLkTikw0bwRedjAOMqFXGJ73jEmh-pXOuLfKQENrB77@mail.gmail.com><010e01cbac34$c3983480$c2482dae@Ken1><AANLkTimhrGmoUa=attiP4TkQxa73QJK9-vVdvoM2free@mail.gmail.com><019b01cbac57$659e0c60$c2482dae@Ken1><AANLkTikJRLQ3ahx+4Hvbe2m-W7stiT61ZXbVGpafQpiZ@mail.gmail.com><023701cbac63$48c06820$c2482dae@Ken1><AANLkTimEM+3KetvWNGMwyXjMG02nWZt+c3XieMe1T4PB@mail.gmail.com>


----- Original Message -----
From: "Dienekes Pontikos" <>
To: <>
Sent: Tuesday, January 04, 2011 4:13 PM
Subject: Re: [DNA] How old is Y-Chromosome Adam?


Not sure how you're getting those estimates, or if in what sense they
are better than Ballantyne's, but thanks for the effort.

[[ In each case Ballantyne quotes number n of mutations seen and number N of
father/son transitions observed. I just augment his number of mutations
seen by one and divide by number of father/son transitions observed, hence
getting (n+1)/N = average value of distributions m^n e^(-Nm) Ballantyne
seems to have set his median value at something like (n+ln2) / N for your
three examples given. KN]]

> DYS436: 0 mutations in 1798 meioses,estimated at 3.84x10-4
> I'd add (1-.69)/1798 to his number to get 5.56 10^-4 = 1/1798
>
> DYS594: 1 mutation in 1635 meioses, estimated at 1.03x10-3
> I'd get 2/1635 = 1.22 10^-3
>
> DYS576: 24 mutations in 1727 meioses, estimated at 1.43x10-2
> I'd get 25/1727 = 1.448 10^-2
>
> The differences in each case are all of order .3 / 1700, while the
> fractional differences of course diminish with increasing mutability.

--
Dienekes' Anthropology Blog: http://dienekes.blogspot.com
Dodecad Ancestry Project: http://dodecad.blogspot.com


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