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From: ET Hunter <>
Subject: [PAFRANKL] Calculating dates
Date: Tue, 10 Jun 2003 14:20:58 -0400

If you break apart the number 8870 into two pieces, 88 and 70, and
subtract each from 100, you get 12 and 30, the number of months in a
year, and the average number of days in a month. Actually, you only
need to use the 88 or 70 if the earlier date has a larger number of days
than the later date, or a larger number of months than the later date.
In that case, when you "borrow" from the third column, mathematically
you are borrowing 100, but only need 30, therefore, the additional
subtraction of 70. If the months are larger in the earlier date, you
would again borrow 100 from the 5th column, but only need 12, therefore
the additional subtraction of 88. Remember, if the earlier date has
fewer days or few months than the later date, do not use the 8870
subtraction; i.e. if you don't have to borrow from the third column,
forget the subtraction of 70, and if you don't have to borrow from the
fifth column, forget the subtraction of 88.

There. That sounds clear as mud, but it's the truth!!

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• [PAFRANKL] Calculating dates by ET Hunter <>